Optimal. Leaf size=219 \[ \frac{(6 b c-a d) (b c-a d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{a^4 \sqrt{b}}+\frac{c \sqrt{c+d x} (6 b c-7 a d)}{4 a^2 x (a+b x)}-\frac{\sqrt{c} \left (15 a^2 d^2-40 a b c d+24 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d x}}{\sqrt{c}}\right )}{4 a^4}+\frac{\sqrt{c+d x} \left (4 a^2 d^2-17 a b c d+12 b^2 c^2\right )}{4 a^3 (a+b x)}-\frac{c (c+d x)^{3/2}}{2 a x^2 (a+b x)} \]
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Rubi [A] time = 0.75348, antiderivative size = 219, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.35 \[ \frac{(6 b c-a d) (b c-a d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{a^4 \sqrt{b}}+\frac{c \sqrt{c+d x} (6 b c-7 a d)}{4 a^2 x (a+b x)}-\frac{\sqrt{c} \left (15 a^2 d^2-40 a b c d+24 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d x}}{\sqrt{c}}\right )}{4 a^4}+\frac{\sqrt{c+d x} \left (4 a^2 d^2-17 a b c d+12 b^2 c^2\right )}{4 a^3 (a+b x)}-\frac{c (c+d x)^{3/2}}{2 a x^2 (a+b x)} \]
Antiderivative was successfully verified.
[In] Int[(c + d*x)^(5/2)/(x^3*(a + b*x)^2),x]
[Out]
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Rubi in Sympy [A] time = 93.0765, size = 206, normalized size = 0.94 \[ - \frac{c \left (c + d x\right )^{\frac{3}{2}}}{2 a x^{2} \left (a + b x\right )} - \frac{\sqrt{c + d x} \left (a d - b c\right ) \left (2 a d - 3 b c\right )}{2 a^{2} b x \left (a + b x\right )} + \frac{\sqrt{c + d x} \left (4 a^{2} d^{2} - 17 a b c d + 12 b^{2} c^{2}\right )}{4 a^{3} b x} - \frac{\sqrt{c} \left (15 a^{2} d^{2} - 40 a b c d + 24 b^{2} c^{2}\right ) \operatorname{atanh}{\left (\frac{\sqrt{c + d x}}{\sqrt{c}} \right )}}{4 a^{4}} + \frac{\left (a d - 6 b c\right ) \left (a d - b c\right )^{\frac{3}{2}} \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{c + d x}}{\sqrt{a d - b c}} \right )}}{a^{4} \sqrt{b}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((d*x+c)**(5/2)/x**3/(b*x+a)**2,x)
[Out]
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Mathematica [A] time = 0.380246, size = 164, normalized size = 0.75 \[ \frac{-\sqrt{c} \left (15 a^2 d^2-40 a b c d+24 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d x}}{\sqrt{c}}\right )+a \sqrt{c+d x} \left (\frac{c (8 b c-9 a d)}{x}+\frac{4 (b c-a d)^2}{a+b x}-\frac{2 a c^2}{x^2}\right )+\frac{4 (6 b c-a d) (b c-a d)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x}}{\sqrt{b c-a d}}\right )}{\sqrt{b}}}{4 a^4} \]
Antiderivative was successfully verified.
[In] Integrate[(c + d*x)^(5/2)/(x^3*(a + b*x)^2),x]
[Out]
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Maple [B] time = 0.028, size = 403, normalized size = 1.8 \[ -{\frac{9\,c}{4\,{a}^{2}{x}^{2}} \left ( dx+c \right ) ^{{\frac{3}{2}}}}+2\,{\frac{{c}^{2} \left ( dx+c \right ) ^{3/2}b}{{a}^{3}d{x}^{2}}}+{\frac{7\,{c}^{2}}{4\,{a}^{2}{x}^{2}}\sqrt{dx+c}}-2\,{\frac{{c}^{3}\sqrt{dx+c}b}{{a}^{3}d{x}^{2}}}-{\frac{15\,{d}^{2}}{4\,{a}^{2}}\sqrt{c}{\it Artanh} \left ({1\sqrt{dx+c}{\frac{1}{\sqrt{c}}}} \right ) }+10\,{\frac{d{c}^{3/2}b}{{a}^{3}}{\it Artanh} \left ({\frac{\sqrt{dx+c}}{\sqrt{c}}} \right ) }-6\,{\frac{{c}^{5/2}{b}^{2}}{{a}^{4}}{\it Artanh} \left ({\frac{\sqrt{dx+c}}{\sqrt{c}}} \right ) }+{\frac{{d}^{3}}{a \left ( bdx+ad \right ) }\sqrt{dx+c}}-2\,{\frac{{d}^{2}\sqrt{dx+c}bc}{{a}^{2} \left ( bdx+ad \right ) }}+{\frac{{b}^{2}d{c}^{2}}{{a}^{3} \left ( bdx+ad \right ) }\sqrt{dx+c}}+{\frac{{d}^{3}}{a}\arctan \left ({b\sqrt{dx+c}{\frac{1}{\sqrt{ \left ( ad-bc \right ) b}}}} \right ){\frac{1}{\sqrt{ \left ( ad-bc \right ) b}}}}-8\,{\frac{{d}^{2}bc}{{a}^{2}\sqrt{ \left ( ad-bc \right ) b}}\arctan \left ({\frac{\sqrt{dx+c}b}{\sqrt{ \left ( ad-bc \right ) b}}} \right ) }+13\,{\frac{{b}^{2}d{c}^{2}}{{a}^{3}\sqrt{ \left ( ad-bc \right ) b}}\arctan \left ({\frac{\sqrt{dx+c}b}{\sqrt{ \left ( ad-bc \right ) b}}} \right ) }-6\,{\frac{{b}^{3}{c}^{3}}{{a}^{4}\sqrt{ \left ( ad-bc \right ) b}}\arctan \left ({\frac{\sqrt{dx+c}b}{\sqrt{ \left ( ad-bc \right ) b}}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((d*x+c)^(5/2)/x^3/(b*x+a)^2,x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x + c)^(5/2)/((b*x + a)^2*x^3),x, algorithm="maxima")
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Fricas [A] time = 0.434999, size = 1, normalized size = 0. \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x + c)^(5/2)/((b*x + a)^2*x^3),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x+c)**(5/2)/x**3/(b*x+a)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.226779, size = 358, normalized size = 1.63 \[ -\frac{{\left (6 \, b^{3} c^{3} - 13 \, a b^{2} c^{2} d + 8 \, a^{2} b c d^{2} - a^{3} d^{3}\right )} \arctan \left (\frac{\sqrt{d x + c} b}{\sqrt{-b^{2} c + a b d}}\right )}{\sqrt{-b^{2} c + a b d} a^{4}} + \frac{{\left (24 \, b^{2} c^{3} - 40 \, a b c^{2} d + 15 \, a^{2} c d^{2}\right )} \arctan \left (\frac{\sqrt{d x + c}}{\sqrt{-c}}\right )}{4 \, a^{4} \sqrt{-c}} + \frac{\sqrt{d x + c} b^{2} c^{2} d - 2 \, \sqrt{d x + c} a b c d^{2} + \sqrt{d x + c} a^{2} d^{3}}{{\left ({\left (d x + c\right )} b - b c + a d\right )} a^{3}} + \frac{8 \,{\left (d x + c\right )}^{\frac{3}{2}} b c^{2} d - 8 \, \sqrt{d x + c} b c^{3} d - 9 \,{\left (d x + c\right )}^{\frac{3}{2}} a c d^{2} + 7 \, \sqrt{d x + c} a c^{2} d^{2}}{4 \, a^{3} d^{2} x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d*x + c)^(5/2)/((b*x + a)^2*x^3),x, algorithm="giac")
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